Given head
which is a reference node to a singly-linked list. The value of each node in the linked list is either 0
or 1
. The linked list holds the binary representation of a number.
Return the decimal value of the number in the linked list.
Example 1:
Input: head = [1,0,1]
Output: 5
Explanation: (101) in base 2 = (5) in base 10
Example 2:
Input: head = [0]
Output: 0
Constraints:
- The Linked List is not empty.
- Number of nodes will not exceed
30
. - Each node's value is either
0
or1
.
solution in cpp
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
int getDecimalValue(ListNode* head) {
int res=0;
ListNode* temp=head;
while(temp)
{
res=(res<<1)+temp->val;
temp=temp->next;
}
return res;
}
};
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