Given a string s
consisting of some words separated by some number of spaces, return the length of the last word in the string.
A word is a maximal substring consisting of non-space characters only.
Example 1:
Input: s = "Hello World"
Output: 5
Explanation: The last word is "World" with length 5.
Example 2:
Input: s = " fly me to the moon "
Output: 4
Explanation: The last word is "moon" with length 4.
Example 3:
Input: s = "luffy is still joyboy"
Output: 6
Explanation: The last word is "joyboy" with length 6.
Constraints:
1 <= s.length <= 104
s
consists of only English letters and spaces' '
.- There will be at least one word in
s
.
solution:
Runtime: 0 ms, faster than 100.00% of C++ online submissions for Length of Last Word.
Memory Usage: 6.5 MB, less than 51.90% of C++ online submissions for Length of Last Word.
class Solution {
public:
int lengthOfLastWord(string s) {
int n=s.length();
bool flag=false;
int cnt=0;
for(int i=n-1;i>=0;i--)
{
if(s[i]>=65&&s[i]<=90||s[i]>=97&&s[i]<=122)
{
cnt++;
flag=true;
}else
{
if(flag)
{
break;
}
}
}
return cnt;
}
};
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