A. Calculating Function
For a positive integer n let's define a function f:
f(n) = - 1 + 2 - 3 + .. + ( - 1)nn
Your task is to calculate f(n) for a given integer n.
The single line contains the positive integer n (1 ≤ n ≤ 1015).
Print f(n) in a single line.
4
2
5
-3
f(4) = - 1 + 2 - 3 + 4 = 2
f(5) = - 1 + 2 - 3 + 4 - 5 = - 3
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soulution:
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#include<iostream>
using namespace std;
int main()
{
long long n, sum;
cin >> n;
if (n % 2 == 0)
sum = (n / 2);
else
sum = ((n + 1) / 2) * (-1);
cout << sum << endl;
return 0;
}
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