Given an integer number n
, return the difference between the product of its digits and the sum of its digits.
Example 1:
Input: n = 234
Output: 15
Explanation:
Product of digits = 2 * 3 * 4 = 24
Sum of digits = 2 + 3 + 4 = 9
Result = 24 - 9 = 15
Example 2:
Input: n = 4421
Output: 21
Explanation:
Product of digits = 4 * 4 * 2 * 1 = 32
Sum of digits = 4 + 4 + 2 + 1 = 11
Result = 32 - 11 = 21
Constraints:
1 <= n <= 10^5
solution:
#include<iostream>
using namespace std;
class Solution {
public:
int subtractProductAndSum(int n) {
int product = 1;
int sum = 0;
while (n != 0)
{
product *= (n % 10);
sum += (n % 10);
n /= 10;
}
return product - sum;
}
};
int main()
{
int n;
cin >> n;
Solution ss;
cout << ss.subtractProductAndSum(n) << "\n";
return 0;
}
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