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Given an integer number n, return the difference between the product of its digits and the sum of its digits.

 

Example 1:

Input: n = 234
Output: 15 
Explanation: 
Product of digits = 2 * 3 * 4 = 24 
Sum of digits = 2 + 3 + 4 = 9 
Result = 24 - 9 = 15

Example 2:

Input: n = 4421
Output: 21
Explanation: 
Product of digits = 4 * 4 * 2 * 1 = 32 
Sum of digits = 4 + 4 + 2 + 1 = 11 
Result = 32 - 11 = 21

 

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Constraints:

  • 1 <= n <= 10^5

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solution:

#include<iostream>
using namespace std;

class Solution {
public:
	int subtractProductAndSum(int n) {
		int product = 1;
		int sum = 0;
		while (n != 0)
		{
			product *= (n % 10);
			sum += (n % 10);
			n /= 10;
		}
		return product - sum;
	}
};

int main()
{
	int n;
	cin >> n;
	Solution ss;
	cout << ss.subtractProductAndSum(n) << "\n";
	return 0;
}

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