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There is a function signFunc(x) that returns:

  • 1 if x is positive.
  • -1 if x is negative.
  • 0 if x is equal to 0.

You are given an integer array nums. Let product be the product of all values in the array nums.

Return signFunc(product).

 

Example 1:

Input: nums = [-1,-2,-3,-4,3,2,1]
Output: 1
Explanation: The product of all values in the array is 144, and signFunc(144) = 1

Example 2:

Input: nums = [1,5,0,2,-3]
Output: 0
Explanation: The product of all values in the array is 0, and signFunc(0) = 0

Example 3:

Input: nums = [-1,1,-1,1,-1]
Output: -1
Explanation: The product of all values in the array is -1, and signFunc(-1) = -1

 

Constraints:

  • 1 <= nums.length <= 1000
  • -100 <= nums[i] <= 100



solution in c++

class Solution {
public:
    int arraySign(vector<int>& nums) {
        long long sum=1;
        for(int i=0;i<nums.size();i++)
        {
            if(nums[i]>0)
                nums[i]=1;
            else if(nums[i]<0)
                nums[i]=-1;
            else
                nums[i]=0;
            sum*=nums[i];
        }
        return sum;
    }
};

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