A special site for solving fun programming problems and challenges, interested in computer science, programming, basics, data structure and algorithms



You are given an array prices where prices[i] is the price of a given stock on the ith day.

You want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock.

Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0.

 

Example 1:

Input: prices = [7,1,5,3,6,4]
Output: 5
Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5.
Note that buying on day 2 and selling on day 1 is not allowed because you must buy before you sell.

Example 2:

Input: prices = [7,6,4,3,1]
Output: 0
Explanation: In this case, no transactions are done and the max profit = 0.

 

Constraints:

  • 1 <= prices.length <= 105
  • 0 <= prices[i] <= 104


 solution in c++

class Solution {
public:
    int maxProfit(vector<int>& prices) {
        int pof=INT_MAX;
        int ans=0;
        for(int i=0;i<prices.size();i++)
        {
            if(prices[i]<pof)
            {
                pof=prices[i];
            }else if(prices[i]-pof>ans)
            {
                ans=prices[i]-pof;
            }
        }
        return ans;
    }
};

No comments:

Post a Comment