You are given an array prices
where prices[i]
is the price of a given stock on the ith
day.
You want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock.
Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0
.
Example 1:
Input: prices = [7,1,5,3,6,4]
Output: 5
Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5.
Note that buying on day 2 and selling on day 1 is not allowed because you must buy before you sell.
Example 2:
Input: prices = [7,6,4,3,1]
Output: 0
Explanation: In this case, no transactions are done and the max profit = 0.
Constraints:
1 <= prices.length <= 105
0 <= prices[i] <= 104
solution in c++
class Solution {
public:
int maxProfit(vector<int>& prices) {
int pof=INT_MAX;
int ans=0;
for(int i=0;i<prices.size();i++)
{
if(prices[i]<pof)
{
pof=prices[i];
}else if(prices[i]-pof>ans)
{
ans=prices[i]-pof;
}
}
return ans;
}
};
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